Test for Divergence (Series)

Test for Divergence

If ∑an converges then an→0.

Proof
Let ε>0. By the Cauchy Condition for series, then choose N∈N such that n>m≥N implies:

|am+1+⋯+an|<ε

In particular, use m=n−1 and any n>N then:

|an|=|an−0|<ε

So by definition then an→0.
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