Test for Divergence (Series)

Test for Divergence

If an converges then an0.

Proof
Let ε>0. By the Cauchy Condition for series, then choose NN such that n>mN implies:

|am+1++an|<ε

In particular, use m=n1 and any n>N then:

|an|=|an0|<ε

So by definition then an0.